Signal to Noise Ratio measurement explained.
The water Raman test is a
good measure of relative sensitivity between different instruments,
provided the experimental conditions used to compare the systems are
the same.
Unfortunately, there are a
number of different ways of handling the data, all of which are valid
but which will give quite different numbers. Therefore, it is
important not only to know how the water Raman S/N values is
measured, but also how the data were treated.
In general, the water
Raman S/N test method combines a value for system sensitivity (in the
presence of a signal) with a value for system noise (in the absence
of signal) to show the overall performance of the instrument.
At Jobin Yvon we define
the S/N ratio as the difference of peak and background signal,
divided by the square root of the Background signal. The peak signal
is measured at the water Raman peak (397 nm for 350 nm excitation)
and the noise in a region (450 nm) where no Raman signal is present,
and an "ideal" system would give a signal value of zero.
Another commonly used
method is to divide the difference (Peak signal - Background signal)
by the rms value of the noise on the background signal. This second
method is used by a few other manufacturers.
Some actual data from our
FluoroLog FL3-11 system (this was a typical system, a few years old)
will serve to show the difference between the two methods.
The experimental
conditions were as follows:
Excitation 350 nm with 5
nm bandpass
Emission 360 - 450 nm with
5nm bandpass
Interval 1nm
Integration 1s
No smoothing of data points
Standard room temperature,
red sensitive, detector (Note: make sure the test is
caried out with the actual detector you will be using. All Spex
systems are specified with a R928P PMT at room temperature).
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The measurements provided
the following data:
Peak signal (at 397nm) =
501,500 cps
Background (at 450 nm) =
10,500 cps
Peak to peak noise of
background (at 450 nm) = 223c (measured with a separate kinetic
scan), which gives an rms noise of the background signal of 223/5 = 44.6 |
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Therefore, the JY method
gives a water Raman S/N of (501500-10500)/ (10500)½
= 4791
The second method
similarly gives a water Raman S/N of (501500-10500)/ 44.6 = 11008
JY feels that the first
method is correct although it gives a lower number. The second method
only takes into account the detector noise and the shot noise of the electronics.
On the other hand, by
using the background total intensity as a measure of noise, the JY
method is more representative of a real "live" experiment
where noise is also influenced by factors like the quality of the
optics and scattered light in the system. These additional factors
will influence the ability to measure a very low signal from a sample
and should not be left out.
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